2^x+3-57=65(2x-1)

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Solution for 2^x+3-57=65(2x-1) equation:



2^x+3-57=65(2x-1)
We move all terms to the left:
2^x+3-57-(65(2x-1))=0
We add all the numbers together, and all the variables
2^x-(65(2x-1))-54=0
We calculate terms in parentheses: -(65(2x-1)), so:
65(2x-1)
We multiply parentheses
130x-65
Back to the equation:
-(130x-65)
We get rid of parentheses
2^x-130x+65-54=0
We add all the numbers together, and all the variables
-130x+2^x+11=0
We move all terms containing x to the left, all other terms to the right
-130x+2^x=-11

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